Question

A large water storage container is filled to a depth of 3.0 m. The volume above the water is filled with air. In order to pump the water from the container, the air pressure in the container is increased by 3.0 105 N/m2. What happens to the pressure in the water at a depth of 1.0 m when the air pressure is increased?

Answer 1

pressure at depth 1 m is 3.098 ×
`10^(5)` N/m²

Step-by-step explanation:

given data

depth = 3 m

air pressure = 3 ×
`10^(5)` N/m²

to find out

pressure at depth 1 m

solution

we know air pressure is 3 ×
`10^(5)` N/m² so at pressure 1 m will be

pressure = air pressure + water pressure at 1 m ............1

water pressure at 1 m is = ρ × g × h

water pressure = 1000 × 9.8 × 1

water pressure = 9800

so from equation 1

pressure = air pressure + water pressure at 1 m

pressure = 3 ×
`10^(5)` + 9800

pressure = 3.098 ×
`10^(5)`

so pressure at depth 1 m is 3.098 ×
`10^(5)` N/m²