Question

A rock is suspended by a light string. When the rock is in air, the tension in the string is 42.2 N . When the rock is totally immersed in water, the tension is 30.6 N . When the rock is totally immersed in an unknown liquid, the tension is 21.0 N . What is the density of the unknown liquid?

Answer 1

1.83 g/cm^3

Step-by-step explanation:

Weight of rock in air = 42.2 N

Weight f rock in water = 30.6 N

Weight of rock in unknown liquid = 21.0 N

The relative density of the unknown liquid is given by the following formula

`relative density of unknown liquid = (weight in air - weight in liquid)/(weight in air - weight in water)`

`relative density of unknown liquid = (42.2-21.0)/(42.2-30.6)`

= 1.83

So, the density of unknown liquid is 1.83 g/cm^3.

Thus, the density of the unknown liquid is 1.83 g/cm^3.