Question

The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6*g, respectively. Determine the speed of the motor . Use g=9.81 m/s^2 .

Answer 1

The speed of shaft is 1891.62 RPM.

Step-by-step explanation:

given that

Amplitude A= 0.15 mm

Acceleration = 0.6 g

So

we can say that acceleration= 0.6 x 9.81

`acceleration,a=5.88\ (m)/(s^2)`

We know that

`a=\omega ^2A`

So now by putting the values

`a=\omega ^2A`

`5.88=\omega ^2 \0.15* 10^(-3)`

`\omega =198.09\ (rad)/(s)`

We know that

ω= 2πN/60

198.0=2πN/60

N=1891.62 RPM

So the speed of shaft is 1891.62 RPM.