Question

What is the equation, in point-slope form, of the line that is

parallel to the given line and passes through the point (-3,
1)?
o y-1=-3(x+3)
y-1=-} (x + 3)
Oy- 1=} (x + 3)
oy-1=3(x+3)
HELP

Answer 1

Answer: D: y - 1 = (3/2) (x + 3)

Explanation:

The very first thing that needs to be done is to calculate the slope of the line shown, as we have to points, we can do it following the equation:

m=(y2 - y1)/(x2 - x1)

We know that the x1,y1 couple is (2,2) and the x2,y2 couple is (-2,-4), then we replace the values on the equation and we have:

m=(-4 - 2)/(-2 - 2) = -6/-4, then we simplify the result and we have 3/2.

We already have the slope of the equation, we are just missing the units that the line is moved to the left. We know that the equation must follow the form y = mx + b, and we already know m, we are missing b on both equations, but, as the line drawn is passing by (0,-1), or the origin, we know that b for that equation is -1. So the equation for that line is:

y = (3/2)x - 1

And the only answer that has the same slope is D.