Question

the perimeter of am equilateral triangle is 7 inches more than perimeter of a square and the side of the triangle is 5 inches more than the side of the square. find the side of the triangle​

Answer 1

Let
`t` be the side of the triangle and
`s` be the side of the square.

Let
`P_t` be the perimeter of the triangle and
`P_s` be the perimeter of the square.

We have the following relationship:

`\begin{cases}P_t = P_s+7\\t=s+5\\P_t = 3t\\P_s=4s\end{cases} \implies \begin{cases}3t=4s+7\\t=s+5\end{cases} \implies 3(s+5)=4s+7 \implies s=8`

Which finally implies

`t=s+5=13`

Answer 2

Side of triangle = 13 inches

Explanation:

Let side of square be x inches.

Perimeter of square = 4*side = 4x --------->1

side of triangle = x+5 { the side of the triangle is 5 inches more than the side of the square. }

Perimeter of triangle = 3*side

= 3 * (x+5) =3x + 15 -------->2

The perimeter of an equilateral triangle is 7 inches more than perimeter of a square.

3x + 15 - 4x = 7

3x -4x = 7-15

-x = - 8

x= 8

Side of a square = 8 inches.

Side of triangle = x + 5 = 8 + 5 = 13 inches