Question

Whoever checks my work and tell what I did wrong and the right answer will

GET.......
30points

Answer 1

See below

Explanation:

I believe that you only had to do letters F, H, and J. In that case, let's go over each one!

F: For isolating
`d_(1)`, we need to get rid of the 1/2 first. Let's multiply each side by 2:

`2*m = 2*(1)/(2)(d_(1)+  d_(2)) \\2m = d_(1)+  d_(2)`

After this, we just subtract
`d_(2)` from each side to get
`d_(1)=2m- d_(2)`. Dark Blue is correct! Let's now plug in those numbers below:

`d_(1)=2(10)- 13 = 20-13=7`

G: Let's isolate the vw^2 on one side by subtracting y from each side:

`vw^(2) +y-y=x-y\\vw^(2)=x-y`

Let's now divide each side by v, then put each side under a square root to get our final answer:

`(vw^2)/(v) = (x-y)/(v)\\  w^2 =  (x-y)/(v)\\√(w^2) = \sqrt{(x-y)/(v)} \\w=\sqrt{(x-y)/(v)}`

Orange is correct! Again, let's solve the problem underneath:

w=
`w=\sqrt{(38-(-7))/(5)} = \sqrt{(38+7)/(5)} = \sqrt{(45)/(5)}=√(9)=3`

H: This one has some stuff that we haven't worked with quite yet (like terms), but our approach is the same: isolate c on one side of the equation.

`2a-2a+3c=17a-2a+21\\3c = 15a+21\\(3c)/(3) = (15a+21)/(3)\\c = (15a)/(3)+ (21)/(3) \\c = 5a+7`

Purple is correct! Let's solve the problem:

`c = 5((16)/(5))+7 = 16+7 = 23`