If the resistivities have the ratio rho2/rho1= 7.00, what is the ratio ΔV1/ΔV2 of the potential differences across the two segments of the wire?

Question

asked Sep 10, 2020 10.5k views

1 Answer

Mosch · Answer 1 · 2020-09-15T01:31:10+0000

Answer:

(1)/(7)

Step-by-step explanation:

We have given the ratio of resistivities
$(\rho _2)/(\rho _1)=7$

The resistance of any material is given by
$R=(\rho l)/(A)$

From the relation we can see that resistance is directly proportional to the resistivity of the material so
(R_2)/(R_1)=7

According to ohm's law we know that V =iR

From this relation we can see that potential difference is directly proportional to the resistance so
$(\Delta V_1)/(\Delta V_2)=(1)/(7)$