Question

If the resistivities have the ratio rho2/rho1= 7.00, what is the ratio ΔV1/ΔV2 of the potential differences across the two segments of the wire?

Answer 1

`(1)/(7)`

Step-by-step explanation:

We have given the ratio of resistivities
`(\rho _2)/(\rho _1)=7`

The resistance of any material is given by
`R=(\rho l)/(A)`

From the relation we can see that resistance is directly proportional to the resistivity of the material so
`(R_2)/(R_1)=7`

According to ohm's law we know that V =iR

From this relation we can see that potential difference is directly proportional to the resistance so
`(\Delta V_1)/(\Delta V_2)=(1)/(7)`