Question

A beaker is filled to the 500 ml mark with alcohol. What increase in volume (in ml) the beaker contain when the temperature changes from 5°C to 30°C? (Neglect the expansion of the beaker, evaporation of alcohol and absorption of water vapor by alcohol.) C°, Palcohol = 1.12 x 104/ °C

Answer 1

1.4 mL

Step-by-step explanation:

Given that:

volume of alcohol
`V_0` = 500

Temperature change ΔT = (30° - 5°)C

=25° C

`\beta_( alcohol )= 1.12 * 10^(-4) / ^0C`

The increase in volume ΔV =
`\alpha * V_o * \Delta T`

`= 500 * 1.12 * 10^(-4) / ^0 C* 25^0 C`

= 1.4 mL