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A space vehicle deploys its re–entry parachute when it's traveling at a vertical velocity of –150 meters/second (negative because the parachute is going down.) It comes to rest at 0 meters/second after 30 seconds. What's the average acceleration of the shuttle during this time span?

A. -0.2 meters/second2
B. -5 meters/second2
C. 0.2 meters/second2
D. 5 meters/second2

User Thisarattr
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2 Answers

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Answer:

D. 5 meters/second2

Step-by-step explanation:

plato

User Alex Dupuy
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2 votes

Answer: OPTION D.

Step-by-step explanation:

We can use the Kinematic formula for an object under constant acceleration:


V_f=V_0+at

Where
V_F is the final velocity,
V_0 is the initial velocity, "a" is the acceleration and "t" is the time.

In this case we know that:


V_f=0\ (m)/(s)\\\\V_0=-150\ (m)/(s)\\\\t=30\ s

Therefore, we must substitute these values into the formula and solve for "a":


0\ (m)/(s)=-150\ (m)/(s)+a(30\ s)\\\\a=(150\ (m)/(s))/(30\ s)\\\\a=5\ (m)/(s^2)

User Pablobart
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