Question

If the density of nitrogen in air is 0.87 g/L, what mass (in kg) of nitrogen is contained in a room with dimensions of 4.0 m x 3.5 m x 2.4 m?

Answer 1

Answer: 29.232 kg

Explanation: First, we must calculate the volume of the room. From the dimensions given in the exercise, we can assume that the room is box-shaped so its volume will be:

`V=4.0m *3.5 m*2.4 m=33.6 m^3`

Since the density of nitrogen in air is given in grams over liter, we must change the volume units from cubic meters to litres.

`V=(33.6m^3)*((1000L)/(1 m^3) )=33600 L`

Now we just have to multiply the volume of the room by the density of nitrogen:

`Mass= 0.87 (g)/(L) *33600L=29232 g`

To report this mass in kilograms, unit conversion is applied:

`Mass=29232g*(1 kg)/(1000 g) =29.232 kg`