Question

The density of nuclear matter is about 1018 kg/m3. Given that 1 mL is equal in volume to 1 cm3, what is the density of nuclear matter in megagrams per microliter (that is, Mg/µL)?

Answer 1

Answer: density of nuclear matter will be
`10^(-12)Mg/\mu L`

Explanation:-

Density is defined as the mass contained per unit volume.

`Density=(mass)/(Volume)`

Given:

Density of nuclear matter=
`1018kg/m^3`

1 ml =
`1cm^3`

1 kg = 0.001 Mg

Thus
`1018kg=(0.001)/(1)* 1018=1.018Mg`

Also
`1m^3=10^9\mu L`

Putting in the values we get:

`Density=(0.001Mg)/(10^9\mu L)=10^(-12)Mg/\mu L`

Thus density of nuclear matter will be
`10^(-12)Mg/\mu L`

Answer 2

density is
`10^(6)` Mg/µL

Step-by-step explanation:

given data

density of nuclear =
`10^(18)` kg/m³

1 ml = 1 cm³

to find out

density of nuclear matter in Mg/µL

solution

we know here

1 Mg = 1000 kg

so

1 m³ is equal to
`10^(6)` cm³

and here 1 cm³ is equal to 1 mL

so we can say 1 mL is equal to 10³ µL

so by these we can convert density

density =
`10^(18)` kg/m³

density =
`10^(18)` kg/m³ ×
`(10^(-3) )/(10^(6) )` Mg/µL

density =
`10^(6)` Mg/µL