Question

An object of mass 5 m is lifted to a height of 5 h above the floor. What is the potential energy the object gained in this process (in the unit of mgh)? The potential change is

Answer 1

When an object with a mass of 5m is lifted to a height of 5h, its potential energy gain is 25mgh, calculated using the formula PEg = mgh.

Step-by-step explanation:

Calculating Gravitational Potential Energy

When an object with a mass 5m is lifted to a height 5h above the floor, the gravitational potential energy it gains can be calculated using the formula PEg = mgh. Gravitational potential energy is the energy that is stored in an object as a result of its position in a gravitational field, commonly Earth's gravity. In this case, the energy gained by the object is easily found by substituting the values for mass (5m) and height (5h) into the formula, yielding a gravitational potential energy change of 25mgh.

The potential energy gain of the object when lifted to height 5h is calculated based on the weight of the object (mass × gravitational acceleration) and the height it is raised. The energy is expressed in terms of mgh, and assuming Earth's standard gravity, the unit for this energy will be in Joules (when mass is in kilograms, height in meters, and gravitational acceleration in meters per second squared).

Answer 2

Potential energy, E = 25 mgh

Step-by-step explanation:

Given that,

Mass of the object, m = 5 m

It is lifted to a height of, h = 5 h

It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :

`E=m* g* h`

`E=5\ m* g* 5\ h`

E = 25 mgh

So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.