Question

The eyepiece of a compound microscope has a focal length of 2.5 cm and the objective lens has a focal length of 0.60 cm. The two lenses are separated by 14 cm. What is the overall magnification of the microscope?

Answer 1

191.67

Step-by-step explanation:

focal length of objective lens, fo = 0.6 cm

focal length of eyepiece, fe = 2.5 cm

Distance between the lenses, L = 14 cm

Least distance of distinct vision for normal eye, d = 25 cm

The formula for the magnification of the compound microscope is given by

`M =-(\left ( L-f_(e) \right )d)/(f_(o)f_(e))`

`M =-\frac {\left ( 14-2.5 \right )25}{0.6 * 2.5}}`

M = - 191.67

Thus, the magnification of the compound microscope is 191.67.