Question

Show the calculation of the mole fraction of each gas in a 1.00 liter container holding a mixture of 8.65 g of CO2 and 4.32 g of SO2 at 25oC.

Answer 1

0.745 and 0.245

Step-by-step explanation:

Mole fraction (χ) is the number of moles of a component divided by the total number of moles in a mixture.

We must calculate the moles of each component.

Let CO₂ be Gas 1 and SO₂ be Gas 2.

1. Calculate the moles of each gas.

`\text{n} _(1) = \text{8.65 g} * \frac{\text{1 mol}}{\text{44.01 g}} = \text{0.1965 mol}\\\\\text{n} _(2) = \text{4.32 g} * \frac{\text{1 mol}}{\text{64.06 g}} = \text{0.067 44 mol}`

2. Calculate the total moles.

`n_{\text{tot}} = \text{n}_(1) + \text{n}_(2) = \text{0.1965 mol} +\text{0.067 44 mol} = \text{0.2640 mol}`

3. Calculate the mole fraction of each component

`\chi_(1) =(0.1965)/(0.2640) = \mathbf{0.745}\\\\\chi_(2) =(0.06744)/(0.2640) = \mathbf{0.255}`