Question

An athlete executing a long jump leaves the ground at a 28.0º angle and travels 7.80 m. (A) What was the takeoff speed?

Answer 1

9.6 m/s

Step-by-step explanation:

Angle of projection, θ = 28°

Horizontal distance, R = 7.8 m

Let the velocity of projection is given by u.

The formula used to find the velocity of projection is given by

`R=(u^(2)Sin2\theta )/(g)`

`7.8=(u^(2)Sin\left (2* 28  \right ) )/(9.8)`

`7.8=(u^(2)* 0.829)/(9.8)`

u = 9.6 m/s

Thus, the velocity of projection is 9.6 m/s.