Question

Calculate the number of cells in a hummingbird assuming the mass of an average cell is ten times the mass of a bacterium

Answer 1

`4* 10^(12)`

Step-by-step explanation:

Given that, the mass of an average cell is 10 times the mass of a bacterium.

And we know that the mass of the bacterium is,

`m_(B) =10^(-15)kg`

Now, the mass of an average cell can be calculate by the mass of bacterium,

`m_(c)=10* m_(B)\\m_(c)=10* 10^(-15)kg\\m_(c)=10^(-14)kg`

And the average mass of the humming bird is,

`m_(H) =4* 10^(-2)kg`

And also we know that,

The no cell is defined as the ratio of mass of an object to the mass of the average cell.

Mathematically,

`N=(m_(H))/(m_(c))`

Therefore,

`N=(4* 10^(-2)kg)/(10^(-14)kg)\\ N=4* 10^(12)`

Therefore, the number of cell in the humming bird is
`4* 10^(12)`