Answer:
![\mu = 2.06 * 10^(-2) P](https://img.qammunity.org/2020/formulas/physics/college/67x5ah74afdbevu732kh2y4nl5ekas3ywa.png)
Step-by-step explanation:
We have that
![1\, P = 1 \, (g)/(s\,cm)](https://img.qammunity.org/2020/formulas/physics/college/m2jctlma5gnk8qtyxvtkhuo9o7u992mwzz.png)
if the viscosity of water at 5°C is:
![\mu = 2.06 * 10^(-3) (kg)/(s\cdot m)](https://img.qammunity.org/2020/formulas/physics/college/907b7apikb0jyemdknh8sjsuqt67xuabn2.png)
To express this quantity in poise, we have to go from SI units to CGS units, we can do that by replacing kilograms by grams and meters by centimeters.
we know that:
![1\, kg = 1000\, g\\\\1\,m = 100 \, cm](https://img.qammunity.org/2020/formulas/physics/college/t38lschmthchgjmp1580ga5fpnez7cnejc.png)
Inserting this into the preceding equation we have:
![\mu = 2.06 * 10^(-3) (kg)/(s\cdot m)= 2.06 * 10^(-3) (1000)/(100) (g)/(s\cdot cm)\\\mu = 2.06 * 10^(-2) (g)/(s\cdot cm) = 2.06 * 10^(-2) P\\\mu = 2.06\,c P](https://img.qammunity.org/2020/formulas/physics/college/i5r61aaptahx245oqadricetn9rd1s5ae7.png)
Where
or centipoise is a hundredth of a poise