Question

45. A particle moves in a straight line with an initial velocity of 30 m/s and constant acceleration 30 m/s2 . (a) What is its displacement at t = 5 s? (b) What is its velocity at this same time?

Answer 1

Velocity at 5 seconds: 180 m/s

Ditance: 525 meters

Step-by-step explanation:

In order to calculate displacement in this option we need to use the formula for distance when an object is experimenting aceleration:

`s=VoT+1/2at^2`

So now we just have to insert the data that we know:

`s=VoT+1/2at^2\\s= 30*5+ 1/2*30*25\\s=150+15*25\\s= 150+375\\s=525 m`

The distance after 5 seconds with an initial velocity of 30 m/s and an acceleration of 30 m/s will be 525 meters.

And the final velocity is calculated by the next formula:

`Vf= Vo+ A*t\\Vf= 30 m/s+ 30m/s*5\\Vf=180m/s`

So the final velocity at 5s would be 180 m/s