Question

What is the magnitude of an electric field that balances the weight of a plastic sphere of mass 2.1 g that has been charged to -3.0 nc ?

Answer 1

Electric field,
`E=6.86* 10^6\ N/C`

Step-by-step explanation:

It is given that,

Mass of sphere, m = 2.1 g = 0.0021 kg

Charge,
`q=-3\ nC=-3* 10^(-9)\ C`

We need to find the magnitude of electric field that balances the weight of a plastic spheres. So,

`ma=qE`

a = g

`E=(mg)/(q)`

`E=(0.0021\ kg* 9.8\ m/s^2)/(-3* 10^(-9)\ C)`

`E=6860000\ N/C`

or

`E=6.86* 10^6\ N/C`

Hence, the magnitude of electric field that balances its weight is
`6.86* 10^6\ N/C`. Hence, this is the required solution.