Question

If 4 people are selected from a group of 6 married couples, what is the probability that none of them would be married to each other?

Answer 1

16/33

Explanation:

12C4(total possible outcomes)=495

Since there are 6 married couples there must be 6*[2C2×10C2]=270

must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255

the no of groupings with no married couples 495-255 =240

probability=no of favourable outcomes /no of possible outcome

probability=240/495= 16/33