Question

H(n) = n^2 - 4n; Find h(-3)

Answer 1

h(-3)= (-3)^2 - 4(-3)

9+12= 21

Answer 2

For this case we have the following function:

`h (n) = n ^ 2-4n`

We must find the value of the function when
`n = -3`.

Substituting we have:

`h (-3) = (- 3) ^ 2-4 (-3)`

We must bear in mind that the law of multiplication signs complies:

`- * - = +`

So:

`h (-3) = 9 + 12\\h (-3) = 21`

Answer:

`h (-3) = 21`