Question

Resistors are assigned a power rating. If the power rating is exceeded significantly, the resistor will overheat and crack. Suppose you have a 11 kΩ, 0.4 watt resistor. What is the maximum voltage it can safely handle (volts)?

Answer 1

The maximum voltage that the 11 kΩ, 0.4 watt resistor can safely handle is 66.33 volts.

Step-by-step explanation:

When a resistor is assigned a power rating, it indicates the maximum power that the resistor can safely handle without overheating and cracking. In this case, you have a 11 kΩ resistor with a power rating of 0.4 watts. To determine the maximum voltage it can safely handle, you can use the formula Power = Voltage^2 / Resistance. Rearranging the formula, we get Voltage = √(Power x Resistance). Plugging in the values, we have Voltage = √(0.4 x 11000) = √4400 = 66.33 volts.

Answer 2

The Maximun voltage is 66.33 volts.

Step-by-step explanation:

According to the statement the power rating is 0.4 watt. we have to find a voltage that give us that power so we can set that value as a limit.

according with Ohm's law

`I=(V)/(R)` (1)

and

`P=V.I` (2)

if we sustitute (1) in (2)

`P= (V^(2))/(R)`

So the voltage that gives a power of 0.4 watt is given by:

`V=√(P*R) =√(0.4*11000)`

`V=66.33 Volts\\`

so 66.33 is the limit, if we apply a voltage greater than 66.33 the resistor will overheat and get destroyed.