Question

A solution was prepared by dissolving 193 mg of potassium sulfate ( K2SO4 , MW = 174.24 g/mol) in 603 mL of water. Use this information to calculate each quantity.

Answer 1

C K2SO4 = 1.837 E-3 M

Step-by-step explanation:

• K2SO4(s) + H2O(l) ↔ 2K+(aq) + SO42-(aq)

∴ m K2SO4 = 193 mg * ( g / 1000 mg ) = 0.193 g

∴ Mw K2SO4 = 174.24 g/mol

∴ Vsln = 603 mL H2O = 0.603 L sln

⇒ mol K2SO4 = 0.193 g * ( mol / 174.24 g ) = 1.108 E-3 mol

⇒ C K2SO4 = 1.108 E-3 mol / 0.603 L = 1.837 E-3 M