Question

Consider the function f(x) = 20/√x and its second-degree polynomial P2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. Compute the value of f(0.8) and P2 (0.8). Round your answer to four decimal places.(A) f(08) = 22.3607 P2(0.8) = 44.6000(B) f(08) = 22.3607 P2(0.8) = 22.3000(C) f(08) = 45.7214 P2(0.8) = 45.6000(D) f(08) = 21.3607 P2(0.8) = 21.3000(E) f(08) = 23.3607 P2(0.8) = 22.3000

Answer 1

`f (0.8) = 22.3607` and
`P_(2) (0.8) = 22.300`.

Explanation:

According to the statement,
`f (x) = (20)/(√(x))` and
`P_(2)(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2`. Based on these definitions, at
`x=0.8` produce:

`f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607`. On the other hand, you have to:

`P_(2) (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2`

`P_(2) (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300`

Then, it can be affirmed that
`f (0.8) = 22.3607` and
`P_(2) (0.8) = 22.300`.