Question

The area of a trapezoid is found with the formula A=

(b
+ b2) h.
A trapezoidal banner has an area of 120 m2 and a height of 10 m. Base 1 (b1)is 16 m shorter than base 2 (b2)
- What are the lengths of the two bases? Let b represent the length of base 1.
Enter your answers in the boxes.
(b1) =_m
(b2) =_m
​

Answer 1

B1=4cm

Explanation:

Answer 2

`b1=4\ m`

`b2=20\ m`

Explanation:

we know that

The area of a trapezoid is

`A=(1)/(2)[b1+b2]h`

where

b1 and b2 are the parallel bases

h is the height of trapezoid

we have

`A=120\ m^2`

`h=10\ m`

`b1=b2-16`

substitute the values in the formula and solve for b2

`120=(1)/(2)[b2-16+b2]10`

Simplify

`24=[2b2-16]`

`b2=40/2\\b2=20\ m`

Find the value of b1

`b1=20-16=4\ m`

therefore

`b1=4\ m`

`b2=20\ m`