Question

An object having a net charge of 25.0 µC is placed in a uniform electric field of 620 N/C directed vertically. What is the mass of this object if it "floats" in the field?

Answer 1

Mass of the object,
`m=1.58* 10^(-3)\ kg`

Step-by-step explanation:

It is given that,

Charge on an object,
`q=25\ \mu C=25* 10^(-6)\ C`

Electric field, E = 620 N/C

We need to find the mass of this object. Let m is the mass of the object. It can be calculated as :

`ma=qE`

`m=(qE)/(a)`, here a = g (as it is vertically downward)

`m=(25* 10^(-6)* 620)/(9.8)`

m = 0.00158 kg

`m=1.58* 10^(-3)\ kg`

So, the mass of the object is
`1.58* 10^(-3)\ kg`. Hence, this is the required solution.