Assumptions:
- Steady state.
- Heat transfer by convection.
- The temperature on the surface of the plate is constant and uniform.
Step-by-step explanation:
According to the attached image, the local heat flux over a flat plate can be expressed as follows,

Where:
![Q : Local \ Heat \ Flux [W]\\T_(s) : Temperature \ on \ the \ surface \ of \ the \ plate \ [K]\\T_(\infty) : Temperature \ of \ the \ room \ [K]\\h : Convective coefficient [(W)/(m^2 K) ]\\A_(s) : Area \ of \ the \ plate [m^(2)]](https://img.qammunity.org/2020/formulas/engineering/college/jnrhdlw7s37m443v1pxi27ludns8ytbrcu.png)
Consider an average convection coefficient,

Answer:
Then, replacing all the values in the previous expression,
