2m+7/4(3/4m-5/2)=3/32+1/3m

Question

asked Jul 6, 2020 163k views

2 Answers

KSev · Answer 1 · 2020-07-07T01:45:50+0000

For this case we have the following equation:

$2m + \frac {7} {4} (\frac {3} {4} m- \frac {5} {2}) = \frac {3} {32} + \frac {1} {3} m$

We apply distributive property on the left side of the equation:

$2m + \frac {21} {16} m- \frac {35} {8} = \frac {3} {32} + \frac {1} {3} m$

We add similar terms from the left side:

$\frac {53} {16} m- \frac {35} {8} = \frac {3} {32} + \frac {1} {3} m$

Add
$\frac {35} {8}$ to both sides:

$\frac {53} {16} m = \frac {3} {32} + \frac {1} {3} m + \frac {35} {8}$

We subtract
$\frac {1} {3} m$ from both sides:

$\frac {53} {16} m- \frac {1} {3} m = \frac {3} {32} + \frac {35} {8}\\\frac {143} {48} m = \frac {1144} {256}\\143m = \frac {1144 * 48} {256}$

We simplify:

$143m=(54912)/(256)\\143m=(13728)/(64)\\143m=(3432)/(16)\\143m=(858)/(4)\\143m=(429)/(2)$

We divide between 143 on both sides:

$m=(429)/(2*143)\\m=(429)/(286)\\m=(33)/(22)\\m=(3)/(2)$

ANswer:

Timothy Nwanwene · Answer 2 · 2020-07-12T19:05:41+0000

Answer:
m=(3)/(2)

Step-by-step explanation:

We have the following equation:

2m+(7)/(4)((3)/(4)m-(5)/(2))=(3)/(32)+(1)/(3)m

We need to isolate
:

2m+(21)/(16)m-(35)/(8)=(3)/(32)+(1)/(3)m

Grouping similar terms:

2m+(21)/(16)m-(1)/(3)m=(3)/(32)+(35)/(8)

(143)/(48)m=(143)/(32)

m=(48)/(32)

Dividing the numerator and the denominator by 16:

m=(3)/(2)