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I need to solve the absolute value for |2x - 7| = |2x + 9| please anything will help thank you!!!

User Dominix
by
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1 Answer

2 votes

Answer:

-1/2

Explanation:

One way: Since both sides have absolute value, you could square both sides to get rid of the absolute value. This will result in a possible quadratic given the degrees inside the squares; I can already tell you know in this cases the variable squares will cancel since the coefficient of x on both sides inside the | | are the same.


(2x-7)^2=(2x+9)^2

Expand both sides using:
(a+b)^2=a^2+2ab+b^2.


4x^2-28x+49=4x^2+36x+81

Subtract
4x^2 on both sides:


-28x+49=36x+81

Add
28x on both sides:


49=64x+81

Subtract
81 on both sides:


49-81=64x

Simplify:


-32=64x

Divide both sides by 64:


(-32)/(64)=x

Reduce the fraction by dividing top and bottom by
32:


(-1)/(2)=x

The solution is -1/2.

Let's check it.


|2((-1)/(2))-7|=|2((-1)/(2))+9|


|-1-7|=|-1+9|


|-8|=|8|


8=8

So x=-1/2 does check out.

Another way: This is for all the people who hate quadratics.

We could consider cases. These cases must be checked.


|2x-7|=|2x+9| is
2x-7=\pm (2x+9)

Let's solve all four of these and then check the solutions.

2x-7=2x+9

Subtract 2x on both sides:

-7=9 (not possible)

Moving on.

2x-7=-(2x+9)

Distribute:

2x-7=-2x-9

Add 2x on both sides:

4x-7=-9

Add 7 on both sides

4x=-2

Divide both sides by 4:

x=-2/4

Simplify:

x=-1/2

We already checked this from before.

User Shahriyar
by
5.7k points