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If P(A)= 0.3 , P (B)= 0.2, and P(A and B)= 0.1 , determine the following probabilities: (a) P( A' ) (b) P (A U B) (c) P(A' INTERSECT B) (d) P [ (A U B)' ] (e) P (A' U B)'

User Eignhpants
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Answer:

Explanation:

Given that P(A)= 0.3 , P (B)= 0.2, and P(A and B)= 0.1

,(a) P( A' )=
1-P(A) = 0.7

(b) P (A U B)=
P(A)+P(B)-P(AB) =0.2+0.2-0.1\\=0.3

(c) P(A' INTERSECT B) =

(d) P [ (A U B)' ] =
P(B)-P(AB) = 0.2-0.1=0.1

(e) P (A' U B)'=
1-P(AB)\\=0.9

User TomaszKane
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