Question

Drag the tiles to the correct boxes to complete the pairs. Find the distance between each pair of points. 5 units 4 units 2 units 3 units 6 units A (5, 4) and B( 5, -2) arrowRight E(-2, -1) and F(-2, -5) arrowRight C(-4, 1) and D(1, 1) arrowRight G(3, -5) and H(6, -5) arrowRight

Answer 1

person before me is right

A (5, 4) and B (5, -2) = 6 units.

E (-2, -1) and F ( -2, -5) = 4 units.

C (-4, 1) and D (1, 1) = 5 units.

G (3, -5) and H (6, -5) = 3 units.

Answer 2

a) Distance between points A (5, 4) and B( 5, -2) is 6 units

b) Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) Distance between points G(3, -5) and H(6, -5) is 3 units

Explanation:

We need to find the distance between each pair

a) A (5, 4) and B( 5, -2)

the distance formula is:

`d(A,B) = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

Putting values: x₁ = 5, x₂=5 and y₁= 4 and y₂= -2

`d(A,B) = √((5-5)^2+(-2-4)^2)`

`d(A,B) = √((0)^2+(-6)^2)`

`d(A,B) = √(36)`

`d(A,B) = 6`

Distance between points A (5, 4) and B( 5, -2) is 6 units

b) E (-2, -1) and F( -2, -5)

the distance formula is:

`d(E,F) = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

Putting values: x₁ = -2, x₂=-2 and y₁= -1 and y₂= -5

`d(E,F) = √((-2-(-2))^2+(-5-(-1))^2)`

`d(E,F) = √((0)^2+(-4)^2)`

`d(E,F) = √(16)`

`d(E,F) = 4`

Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) C (-4, 1) and D( 1, 1)

the distance formula is:

`d(C,D) = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

Putting values: x₁ = -4, x₂=1 and y₁= 1 and y₂= 1

`d(C,D)= √((1-(-4))^2+(1-(1))^2)`

`d(C,D) = √((5)^2+(0)^2)`

`d(C,D) = √(25)`

`d(C,D) = 5`

Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) G(3, -5) and H(6, -5)

the distance formula is:

`d(G,H) = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

Putting values: x₁ = 3, x₂=6 and y₁= -5 and y₂= -5

`d(G,H)= √((6-(3))^2+(-5-(-5))^2)`

`d(G,H) = √((3)^2+(0)^2)`

`d(G,H) = √(9)`

`d(G,H) = 3`

Distance between points G(3, -5) and H(6, -5) is 3 units