Answer:

Step-by-step explanation:
initial speed of the aircraft = 0
it covers a distance = 100 m
time taken by it = 53 s
so we will have



now we know that there are two forces on the aircraft
1) applied force in forward direction
2) friction force in opposite direction
so we will have




so net force by 60 officers is 53440 N
so force due to each officer is given as
