Question

I need help finishing this table, the equation is 'y=x²+2'​

Answer 1

Answer: 2, 3, 6, 11, 18, 27

Explanation:

Plug the x-value into the equation y = (x)² + 2 to solve for the y-value.

`\begin{array}l\underline{\quad x\quad }&\underline{(x)^2+2=}&\underline{\quad y\quad}\\0&(0)^2+2=&2\\1&(1)^2+2=&3\\2&(2)^2+2=&6\\3&(3)^2+2=&11\\4&(4)^2+2=&18\\5&(5)^2+2=&27\end{array}`