Question

A parallel plate capacitor has a potential difference between its plates of 1.2 V and a plate separationdistance of 2.0 mm. What is the magnitude of the electric field if a material that has a dielectric constant of 3.3 is inserted between the plate

Answer 1

`E_(med) = 181.8 V/m`

Step-by-step explanation:

Potential difference between the plates of capacitor is given as

`\Delta V = 1.2 V`

distance between the plates is given as

`d =  2mm`

so now we have

`E . d = \Delta V`

`E = (\Delta V)/(d)`

`E = (1.2)/(0.002)`

`E = 600 V/m`

now the dielectric of constant 3.3 is inserted between the plates

so we know that

`E_(med) = (E)/(k)`

so we have

`E_(med) = (600)/(3.3)`

`E_(med) = 181.8 V/m`