Question

In a population that is in Hardy-Weinberg equilibrium, 64% of the individuals express the recessive phenotype for a particular gene locus. What is the expected frequency of the recessive allele in this population?

Answer 1

Expected frequency of the recessive allele in this population
`= 80`%

Step-by-step explanation:

Given -

Recessive phenotype expressed by an individuals for a particular gene locus is
`64`%

Now as per Hardy-Weinberg equilibrium equation, the frequency of individual with recessive phenotype is represented by "
`q^(2)`"

where "q" is the frequency for recessive allele.

Thus,

q
`= √(q^2) \\= √(0.64) \\= 0.8\\`

Expected frequency of the recessive allele in this population
`= 80`%