Question

What is the distance between (-1, 4) and (1, -1)

Answer 1

Here
X1=-1, y1=4
X2=1, y2=-1

We have d=under root (x2-x1)sq+y2-y1)sq
=(1-(-1)sq + (-1-4)
=2sq+-5sq
=4+25
=29ans

Answer 2

D(distance)=
`√(29)` or 5.3852, approximately.

Explanation:

Distance formula:
`d=\sqrt{(x_(2) -x_(1) )^(2)+(y_(2) -y_(1) )^(2) } .`

1. Name the variables.

Let -1 be
`x_(1)`. Therefore, 4 will be
`y_(1)`.

Let 1 be
`x_(2)`. Therefore, -1 will be
`y_(2)`.

2. Substitute the values in the formula and calculate.

`d=\sqrt{((1) -(-1) )^(2)+((-1) -(4) )^(2) } \\ \\d=\sqrt{(1+1 )^(2)+(-1-4 )^(2) }\\ \\d=\sqrt{(2 )^(2)+(-5 )^(2) }\\ \\d=√(4+25 )\\ \\d=√(29)`

3. Express the result.

D(distance)=
`√(29)` or 5.3852, approximately.