Question

A point charge is placed 3 m from a 4 μC charge. What is the strength of the electric field on the point charge at this

distance?

Answer 1

`E \approx 3996 \ (N)/(C)`

Step-by-step explanation:

To determine the strength of the electric field produced by a point charge, we can use Coulomb's law. Coulomb's law states that the electric field strength, "E," created by a point charge, "Q," at a certain distance, "r," from the charge is given by the equation:

`E=(k||Q||)/(r^2)`

Where:

• "E" is the electric field strength

• "k" is Coulomb's constant (k ≈ 8.99×10⁹ Nm²/C²)

• "Q" is the charge of the source (in this case, 4 μC, which is equivalent to 4×10⁻⁶ C)

• "r" is the distance from the charge (in this case, 3 m)

Substituting the values into the equation:

`\Longrightarrow E=((8.99*10^9)(4*10^(-6)))/((3)^2)\\\\\\\\\therefore \boxed{\boxed{E \approx 3996 \ (N)/(C) }}`