Question

In a Cavendish experiment that first measured gravity, a 0.730 kg lead ball was placed 0.230 m away from a 158 kg lead ball. How much gravitational force did that create?

Answer 1

Coefficient: 1.45 (enter the answer in proper scientific notation)

Exponent: -7

Step-by-step explanation:

Coefficient must be between 1 and 10

Answer 2

Answer:
`1.45(10)^(-7) N`

Step-by-step explanation:

According to Newton's law of Gravitation, the force
`F` exerted between two bodies of masses
`m1` and
`m2` and separated by a distance
`r` is equal to the product of their masses and inversely proportional to the square of the distance:

`F=G((m1)(m2))/(r^2)`

Where:

`G=6.674x10^(-11)(m^(3))/(kgs^(2))`is the gravitational constant, which was thanks to Cavendish experiment

`m1=0.730 kg`

`m2=158 kg`

`r=0.230 m`

`F=6.674x10^(-11)(m^(3))/(kgs^(2))((0.730 kg)(158 kg))/((0.230 m)^2)`

Solving:

`F=0.000000145 N= 1.45(10)^(-7) N`