Question

Kyle starts from rest and accelerates for 4.6 s. If he is moving at 55 m/s, what is his

acceleration?

Answer 1

Answer:
`11.96 m/s^(2)`

Explanation:

Acceleration
`a` is defined as the variation of Velocity
`\Delta V` in time
`\Delta t`:

`a=(\Delta V)/(\Delta t)`

If we know Kyle started from rest and then had a velocity of 55m/s, then
`\Delta V=55m/s` and
`\Delta t=4.6 s`

Therfore:

`a=(55m/s)/(4.6 s)`

`a=11.96m/s^(2)` This is Kyle's acceleration