Question

A piece of iron with a mass of 119 g is placed in a graduated cylinder, where the water level is to 57 mL. The water level rises to 72 mL. What is the density of the iron

Answer 1

`\rho = 7.93 g/mL`

Step-by-step explanation:

Initial level of water in the cylinder is given as

`V_i = 57 mL`

final level of volume in the cylinder is given as

`V_f = 72 mL`

so volume displaced by the iron piece is given as

`\Delta V = V_f - V_i`

`\Delta V = 72 - 57`

`\Delta V = 15 mL`

so by Archemedies principle the volume displaced by the object is always equal to the volume of the object itself

so here volume of object is 15 mL

mass of the iron piece is 119 g

so here the density of the iron piece is given as

`\rho = (m)/(V)`

`\rho = (119)/(15)`

`\rho = 7.93 g/mL`