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What is the smallest separation between two slits that will produce a second-order minimum for 762 nm red light?

User RootHacker
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1 Answer

3 votes

Answer:

1524 nm.

Step-by-step explanation:

Angular separation of n th minima is given by the expression

Sin θ = n λ / a

Where λ is wavelength of light used and a is separation between two slits .

a = n λ / sin θ

For a to be minimum, sinθ has to be maximum .

maximum value of sin of any angle is 1 .

so the relation becomes as follows

a = n λ

n = 2 , λ = 762 nm.

a = 2 x 762 nm

= 1524 nm.

User Cogslave
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