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Give the values of ΔHo, ΔSo, and T, determine ΔGo and indicate if the reaction is spontaneous. ΔHo = 115 kJ , ΔSo = 263 J/K , and T = 615K ΔGo=___ kJ Spontaneous? yes or no

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Answer:


\Delta G^0=-46.745\ kJ


\Delta G^0<0, the reaction is spontaneous.

Step-by-step explanation:

The expression for the standard change in free energy is:


\Delta G^0=\Delta H^0-T* \Delta S^0

Given that:


\Delta H^0=115\ kJ


T=615\ K


\Delta S^0=263\ J/K

Also, 1 J = 10⁻³ kJ

So,


\Delta S^0=0.263\ kJ/K

Applying in the above formula as:


\Delta G^0=115-615* 0.263\ kJ


\Delta G^0=-46.745\ kJ

Since,
\Delta G^0<0, the reaction is spontaneous.

User Chris Lindseth
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