Question

A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of Ca2 Ca2 per liter (mEq/L) for this solution

Answer 1

Answer: There will be 0.00002 meq per Liter of the solution.

Step-by-step explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

`Normality=\frac{\text{no of gram equivalents} * 1000}{\text{Volume in ml}}`

`Normality=\frac{\text{given mass}* 1000}{\text {Equivalent mass}* {\text{Volume in ml}}}`

Equivalent weight is calculated by dividing the molecular weight by n factor.
`{\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}`

n= charge for charged species , For
`Ca^(2+)` , n =2

`{\text{Equivalent weight}}=(40)/(2)=20g`

`\text{no of gram equivalents}=(0.775g)/(20g/mol)=0.04gramequivalents`

`Normality=(0.04* 1000)/(1925)=0.02eq/L=0.00002meq/L`

Thus there will be 0.00002 meq per Liter of the solution.