Question

X+2y+3z=31
Solve for the variables.

Answer 1

• x = 31 - 2y - 3z
• y = (31 - x - 3z)/2
• z = (31 -x -2y)/3

Explanation:

Subtract the terms not containing the variable of interest, then divide by the coefficient of the variable.

x = 31 -2y -3z . . . . . the coefficient of x is 1, so we're done

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2y = 31 -x -3z

y = (31 -x -3z)/2

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3z = 31 -x -2y

z = (31 -x -2y)/3