Question

Create a 4x5 matrix with ones everywhere and zeros on the last row.

Answer 1

#include <iostream>

using namespace std;

int main() {

int a[4][5];//declaring a matrix of 4 rows and 5 columns.

for(int i=0;i<4;i++)

{

for(int j=0;j<5;j++)

{

if(i==3)//initializing last row as 0.

{

a[i][j]=0;

}

else//initializing last row as 1.

{

a[i][j]=1;

}

}

}

for(int i=0;i<4;i++)

{

for(int j=0;j<5;j++)

cout<<a[i][j]<<" ";//printing the matrix.

cout<<endl;

}

return 0;

}

Output:-

1 1 1 1 1

1 1 1 1 1

1 1 1 1 1

0 0 0 0 0

Step-by-step explanation:

I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.