Question

28.5g of iron shot is added to a graduated cylinder contaning 45.50ml of water. The water level rises to the 49.10 ml mark, from this information, caculate the density of iron

Answer 1

7.92 g/ml

Step-by-step explanation:

Given that, the volume of water in the graduated cylinder is,

`V_(w)=45.50 ml`

Volume of (water+iron shot) is,

`V_(w+Fe)=49.10 ml`

Now the volume of iron shot can be calculate as,

`V_(Fe)=V_(w+Fe)-V_(w)\\V_(Fe)=49.10 ml-45.50 ml\\V_(Fe)=3.6 ml`

And the mass of the iron shot which is given is 28.5 g.

Now the density can be calculated as,

`D=(m)/(V)`

Here, m is the mass, V is the volume

Now,

`D=(28.5)/(3.6)\\D=7.92 gm/ml`

Therefore, the density of iron is 7.92 g/ml.