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How do i solve 4x^2-9?

User Skrtbhtngr
by
8.5k points

2 Answers

7 votes

Answer:

x = 3/2 or x = -3/2

Explanation:

Solve for x over the real numbers:

4 x^2 - 9 = 0

The left hand side factors into a product with two terms:

(2 x - 3) (2 x + 3) = 0

Split into two equations:

2 x - 3 = 0 or 2 x + 3 = 0

Add 3 to both sides:

2 x = 3 or 2 x + 3 = 0

Divide both sides by 2:

x = 3/2 or 2 x + 3 = 0

Subtract 3 from both sides:

x = 3/2 or 2 x = -3

Divide both sides by 2:

Answer: x = 3/2 or x = -3/2

User Zantafio
by
7.9k points
3 votes
Use the PEMDAS method!
User Kyryl Zotov
by
8.1k points

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