Question

Potassium acid phthalae KHC6H4O4 or KHP, is used in many labortries including general chemistry batteries to standardrize solution of base.KHP is one of only a few stable solid acids that can be dried by warming and weighed. A 0.3420 g sample of KHC6H4OH reacts with 35.73 mL of solution in a titration. what is the molar concentration of the

NaOH KHC6H4O4 +NaOH ? KNaC6H4O4 + H2O

Answer 1

Answer: The molarity of NaOH solution is 0.039 M.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Given mass of KHP = 0.3420 g

Molar mass of KHP = 204.22 g/mol

Putting values in above equation, we get:

`\text{Moles of KHP}=(0.3420g)/(204.22g/mol)=0.0014mol`

The chemical reaction for the formation of chromium oxide follows the equation:

`KHC_6H_4O_4(aq.)+NaOH\rightarrow KNaC_6H_4O_4(aq.)+H_2O(l)`

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.0014 moles of KHP will react with =
`(1)/(1)* 0.0014=0.0014mol` of NaOH.

To calculate the molarity of NaOH, we use the equation:

`\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}`

We are given:

Moles of NaOH = 0.0014 moles

Volume of solution = 35.73 mL = 0.03573 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

`\text{Molarity of NaOH }=(0.0014mol)/(0.03573L)=0.039M`

Hence, the molarity of NaOH solution is 0.039 M.