Answer: The percent gallium in gallium bromide is 30.30 %.
Step-by-step explanation:
To calculate the number of moles, we use the equation:
.....(1)
Given mass of gallium bromide = 0.165 g
Molar mass of titanium gallium bromide = 229.53 g/mol
Putting values in equation 1, we get:
![\text{Moles of gallium bromide}=(0.165g)/(229.53g/mol)=0.00072mol](https://img.qammunity.org/2020/formulas/chemistry/college/g3s4safi0kl6k9j76f8y0a9po8k9biz26j.png)
- The chemical equation for the reaction of gallium bromide and silver nitrate follows:
![GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2](https://img.qammunity.org/2020/formulas/chemistry/college/zzzg7z4fke5xxa5jvh1d79yny3wq7o13ti.png)
By Stoichiometry of the reaction:
1 moles of gallium bromide produces 1 mole of gallium nitrate
So, 0.00072 moles of gallium bromide will produce =
of gallium nitrate
- Now, calculating the mass of gallium nitrate from equation 1, we get:
Molar mass of gallium nitrate = 193.73 g/mol
Moles of gallium nitrate = 0.00072 moles
Putting values in equation 1, we get:
![0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g](https://img.qammunity.org/2020/formulas/chemistry/college/ms7rx19a1u9g5eiyl8hlzzapnewap3cnk3.png)
Calculating the mass of gallium in the reaction, we use unitary method:
In 1 mole of gallium nitrate, 1 mole of gallium atom is present.
In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.
So, in 0.139 grams of gallium nitrate, the mass of gallium present will be =
![(69.72)/(193.73)* 0.139=g](https://img.qammunity.org/2020/formulas/chemistry/college/v6hxejhv0itxoa6qwhcj6c3q20ynl7zmm0.png)
- To calculate the percentage composition of gallium in gallium bromide, we use the equation:
![\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}* 100](https://img.qammunity.org/2020/formulas/chemistry/college/6mlvsrfnvq6qhqtm8gdyohju5xnfd165sb.png)
Mass of gallium bromide = 0.165 g
Mass of gallium = 0.050 g
Putting values in above equation, we get:
![\%\text{ composition of gallium}=(0.050g)/(0.165g)* 100=30.30\%](https://img.qammunity.org/2020/formulas/chemistry/college/yhxneusmstiubp7wvcom9h9ducggdo8pod.png)
Hence, the percent gallium in gallium bromide is 30.30 %.