Question

A canoe requires 8 hours of fabrication and a rowboat 5 hours. The fabrication departments has at most 107 hours of labor available each week. Let X be the number of canoes and let Y be the number of rowboats. Select the correct letter for answerA) 8x+5y<107B) 5x+8y<107C) 8x+5y>107D) 5x+8y>107

Answer 1

The correct inequality representing the constraint on the number of canoes and rowboats that can be fabricated given a labor hour limit is 8x + 5y < 107.

Step-by-step explanation:

The correct answer to the question about the number of canoes and rowboats that can be fabricated given the labor hours constraint is 8x + 5y < 107. This inequality represents the maximum number of hours the fabrication department can work in a week using 'x' to represent the number of canoes and 'y' for the number of rowboats. Since each canoe requires 8 hours of labor and each rowboat requires 5 hours, the total labor used for any number of canoes and rowboats must be less than or equal to 107 hours.

Answer 2

Answer: A

Step-by-step explanation: Canoe → 8h →X

Rowboat → 5h → Y

Fabrication department has at most 107, which means it need to be less than 107 hours.

This way, the amount of time to fabricate X canoes = 8X plus the amount of time to fabricate Y Rowboat = 5Y must be less than 107.

8X + 5Y < 107